96=0.06(v^2)

Solution for 96=0.06(v^2) equation:

96=0.06(v^2)

We move all terms to the left:

96-(0.06(v^2))=0

We get rid of parentheses

-0.06v^2+96=0

a = -0.06; b = 0; c = +96;
Δ = b2-4ac
Δ = 02-4·(-0.06)·96
Δ = 23.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{23.04}}{2*-0.06}=\frac{0-\sqrt{23.04}}{-0.12}
=-\frac{\sqrt{}}{-0.12}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{23.04}}{2*-0.06}=\frac{0+\sqrt{23.04}}{-0.12}
=\frac{\sqrt{}}{-0.12}
$